Asked by EddieG
The length of a pool is 3 feet more than twice its width. If the perimeter of the pool is 72 feet, find the dimensions of the pool by writing and solving a system of equations.
Answers
Answered by
Henry
Width = W Ft.
Length = (2W + 3)Ft
P = 2W + 2(2W+3) = 72
2W + 4W+6 = 72
6W = 72-6 = 66
W = 11 Ft.
Length = 2*11 + 3 = 25 Ft
Length = (2W + 3)Ft
P = 2W + 2(2W+3) = 72
2W + 4W+6 = 72
6W = 72-6 = 66
W = 11 Ft.
Length = 2*11 + 3 = 25 Ft
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.