find derivitive of 1/square root of x

1/square root of x = x^(-1/2)

The derivative is -1/2 x^(-3/2)

can you keep going on the problem to not have negative exponents?

You can also use that the derivative of
1/f(x) is given by:

-f'(x)/[f(x)]^2

If you take f(x) = sqrt(x) and use that f'(x) = 1/[2*sqrt(x)], you find that the derivative is given by:

-1/2 * 1/[sqrt(x)]^3

Similar Questions

Add and Subtract Radicals Quick CheckMath 8 Q2 (Pre-Algebra) / Roots and Irrational Numbers add 2 square root 21 + 3 square root
1. 1 answer
Add and Subtract Radicals Quick CheckMath 8 Q2 (Pre-Algebra) / Roots and Irrational Numbers add 3 square root 21 + 7 square root
1. 1 answer
Express in simplest radical form.square root of, 3, x, end square root 3x Answer Multiple Choice Answers square root of, 3,
1. 1 answer
Find the derivative of f(x) = (square root of x)(ln x).Using my notes, I came up with f'(x) = (1/2*square root of x)/x The
1. 2 answers