Asked by Chelsey
A 630. mL flask contains O2 at a pressure of 0.75 atm and a temperature of 20°C. What mass of O2 is present?
I know you Use PV = nRT and solve for n = number of mols gas. Then n = grams/molar mass and solve for grams.
But I get the wrong answer
I know you Use PV = nRT and solve for n = number of mols gas. Then n = grams/molar mass and solve for grams.
But I get the wrong answer
Answers
Answered by
DrBob222
Show your work and let us find the error. A common error is not using kelvin for temperature. Also remember volume must be in L
Answered by
Chelsey
630 ml= 1l= 1000ml
0.63 L
20=293.15 k
0.75*0.63=n*0.0821*293.15
=1687.13002
0.63 L
20=293.15 k
0.75*0.63=n*0.0821*293.15
=1687.13002
Answered by
DrBob222
630 mL = 0.630 L; right.
20 C is 20+273 = 293K; right.
0.75atm x 0.630L = n*0.08206*293
n = 0.0196 mols. I suspect you just punched in the wrong numbers or hit the wrong button somewhere on your calculator. Also you quit when you had n.
Then n = grams/molar mass
0.0196 = g/32
g = 32*0.0196 = approx 0.64 g
20 C is 20+273 = 293K; right.
0.75atm x 0.630L = n*0.08206*293
n = 0.0196 mols. I suspect you just punched in the wrong numbers or hit the wrong button somewhere on your calculator. Also you quit when you had n.
Then n = grams/molar mass
0.0196 = g/32
g = 32*0.0196 = approx 0.64 g
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.