Asked by Robert
you push a 15kg cart with a force of 20N, 30 degrees below the horizontal. what is the normal force? Please help test tomorrow.
Answers
Answered by
bobpursley
normal force downward:
mg+ 20sin30
mg+ 20sin30
Answered by
Robert
It says nothing about friction, so assume its frictionless.
Answered by
Damon
Is it on a level road?
If so
m g + 20 sin 30
15 * 9.81 + 10
If so
m g + 20 sin 30
15 * 9.81 + 10
Answered by
Robert
can you explain the 20sin30?
Answered by
bobpursley
it is the downward component of the 20 N force you are pushing.
Answered by
Robert
Thank you so much!
Answered by
Damon
You are welcome :)
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