Question
you push a 15kg cart with a force of 20N, 30 degrees below the horizontal. what is the normal force? Please help test tomorrow.
Answers
bobpursley
normal force downward:
mg+ 20sin30
mg+ 20sin30
Robert
It says nothing about friction, so assume its frictionless.
Damon
Is it on a level road?
If so
m g + 20 sin 30
15 * 9.81 + 10
If so
m g + 20 sin 30
15 * 9.81 + 10
Robert
can you explain the 20sin30?
bobpursley
it is the downward component of the 20 N force you are pushing.
Robert
Thank you so much!
Damon
You are welcome :)