Asked by Robert

you push a 15kg cart with a force of 20N, 30 degrees below the horizontal. what is the normal force? Please help test tomorrow.

Answers

Answered by bobpursley
normal force downward:

mg+ 20sin30
Answered by Robert
It says nothing about friction, so assume its frictionless.
Answered by Damon
Is it on a level road?
If so

m g + 20 sin 30

15 * 9.81 + 10
Answered by Robert
can you explain the 20sin30?
Answered by bobpursley
it is the downward component of the 20 N force you are pushing.
Answered by Robert
Thank you so much!
Answered by Damon
You are welcome :)
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