Asked by jackie nicole
how in the world do you solve this...
4cos^2x -3 =0
add three to both sides, divide both sides by four, then, take the square root of both sides.
f(x)=x'3+7x'2-x-7 find Zeros,solutions, answers, roots,and x-intercept
4cos^2x -3 =0
add three to both sides, divide both sides by four, then, take the square root of both sides.
f(x)=x'3+7x'2-x-7 find Zeros,solutions, answers, roots,and x-intercept