I have 2 questions. one is a rectangle that has an area of 34 square meters, the width is (x+4)m and the length is (x+11)m. The other problem is a triangle that has an area of 119 square ft. The legs are (x+3) ft and (x+6) ft. It has a right angle opposite the hippotenuse. They both ask to find the dimensions. This is in the factoring trinomials using xsquared + bx + c

2 answers

(x+4)(x+11) = 34
x^2 + 15 x + 44 = 34

x^2 + 15 x + 10 = 0

x = [ -15 + /- sqrt (225 -40)/2

x = [ -15 +/- 13.6 ] / 2

x = -14.3 or - .7

discard -14.3 because negative length and with would result
so use x = -.7
(1/2)(x+3)(x+6) = 119

x^2 + 9 x + 18 = 238

x^2 + 9 x - 220 = 0

(x+20)(x-11) = 0

x = 11
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