Asked by SDW
how would you prepare 445 grams of solution containing 13% mass HCL from 34.1 mass % of HCL solution
Answers
Answered by
DrBob222
Just use the dilution formula.
mass1 x %1 = mass 2 x %2
Substitute and solve.
mass1 x %1 = mass 2 x %2
Substitute and solve.
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