CuO + H2 ==> Cu + H2O
mols CuO = grams/molar mass
Using the coefficients in the balanced equation, convert mols CuO to mols Cu.
Then g Cu = mols Cu x atomic mass Cu.
mols CuO = grams/molar mass
Using the coefficients in the balanced equation, convert mols CuO to mols Cu.
Then g Cu = mols Cu x atomic mass Cu.
The balanced equation for the reaction is:
CuO + H2 -> Cu + H2O
From the balanced equation, we can see that 1 mole of CuO reacts with 1 mole of H2 to produce 1 mole of Cu.
Step 1: Find the molar mass of CuO
Copper (Cu) has a molar mass of 63.55 g/mol, and Oxygen (O) has a molar mass of 16.00 g/mol. Thus, CuO has a molar mass of:
63.55 g/mol + 16.00 g/mol = 79.55 g/mol
Step 2: Calculate the number of moles of CuO
Using the given mass of CuO (34.0 g) and its molar mass (79.55 g/mol), we can calculate the number of moles as follows:
34.0 g / 79.55 g/mol = 0.427 mol
Step 3: Calculate the number of moles of Cu
Since the stoichiometry of the reaction is 1:1, the number of moles of Cu is also 0.427 mol.
Step 4: Find the mass of Cu
Using the molar mass of Cu (63.55 g/mol), we can calculate the mass of Cu as follows:
0.427 mol x 63.55 g/mol = 27.22 g
Therefore, the mass of copper that can be obtained when 34.0 g of copper(II) oxide is used is 27.22 g.
1. Start by writing the balanced chemical equation for the reaction:
CuO + H2 → Cu + H2O
According to the equation, for every 1 mole of CuO, we produce 1 mole of Cu.
2. Calculate the molar mass of copper(II) oxide (CuO):
Cu: 63.55 g/mol
O: 16.00 g/mol
Molar mass of CuO: 63.55 g/mol + 16.00 g/mol = 79.55 g/mol
3. Determine the number of moles of CuO in 34.0 g:
Number of moles = mass / molar mass
Number of moles = 34.0 g / 79.55 g/mol
4. Calculate the number of moles of copper produced:
From the balanced equation, the stoichiometric ratio between CuO and Cu is 1:1.
5. Finally, calculate the mass of copper produced:
Mass of Cu = moles of Cu x molar mass of Cu
By following these steps, you can determine the mass of copper that can be obtained from 34.0 g of copper(II) oxide.