Asked by Grace
In 1901, Thomas Edison invented the nickel-iron battery. The follwing reaction takes place in the battery.
Fe(s) + 2 NiO(OH)(s) + 2 H2O(l) Fe(OH)2(s) + 2 Ni(OH)2(aq)
How many mole of Fe(OH)2, is produced when 3.70 mol Fe and 6.95 mol NiO(OH) react?
Fe(s) + 2 NiO(OH)(s) + 2 H2O(l) Fe(OH)2(s) + 2 Ni(OH)2(aq)
How many mole of Fe(OH)2, is produced when 3.70 mol Fe and 6.95 mol NiO(OH) react?
Answers
Answered by
DrBob222
You need to find the arrow key on your computer and use it. --> or ==> or >>>>.
Using the coefficients in the balanced equation, convert mols each to mols Fe(OH)2.
3.70 mols Fe x (1 mol Fe(OH)2/1 mol Fe) = 3.70 mols Fe.
6.95 mol NiO(OH)2 x (1 mol Fe(OH)2/2 mol NiO(OH)2) = 3.475.
You get two different values which mans one of them is not right. In limiting reagent problems the smaller number ALWAYS wins.
Using the coefficients in the balanced equation, convert mols each to mols Fe(OH)2.
3.70 mols Fe x (1 mol Fe(OH)2/1 mol Fe) = 3.70 mols Fe.
6.95 mol NiO(OH)2 x (1 mol Fe(OH)2/2 mol NiO(OH)2) = 3.475.
You get two different values which mans one of them is not right. In limiting reagent problems the smaller number ALWAYS wins.
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