Asked by Ginny
Could you maybe walk me through this Algebra word problem?
Here is the problem:
Anita wants to put a moat around her rectangular castle. The castle is 45 ft by 60 ft. Let m be the width of the moat.
1. Write a polynomial that represents the total area of the castle and moat.
2. Find the combined area if the moat is 10 feet wide.
3. If the moat is also 10 feet deep, calculate how many gallons of water are in the moat is 1 gallon (almost) = 0.134 ft (cubed). Round the answer to the gallon.
I'm just kinda lost. If you can show me how this problem is done, I'd be really grateful.
Here is the problem:
Anita wants to put a moat around her rectangular castle. The castle is 45 ft by 60 ft. Let m be the width of the moat.
1. Write a polynomial that represents the total area of the castle and moat.
2. Find the combined area if the moat is 10 feet wide.
3. If the moat is also 10 feet deep, calculate how many gallons of water are in the moat is 1 gallon (almost) = 0.134 ft (cubed). Round the answer to the gallon.
I'm just kinda lost. If you can show me how this problem is done, I'd be really grateful.
Answers
Answered by
Steve
If the moat has width m,
castle area = 45*60 = 2700
castle+moat area = (45+2m)(60+2m)
since there is moat on both sides.
moat area = (45+2m)(60+2m)-2700
Now plug in your value for m, and recall that volume is area * depth
castle area = 45*60 = 2700
castle+moat area = (45+2m)(60+2m)
since there is moat on both sides.
moat area = (45+2m)(60+2m)-2700
Now plug in your value for m, and recall that volume is area * depth
Answered by
Ginny
2500ft^2 x 1gal/(0.134ft^2)=~ 186567 gal. Right?
Answered by
Steve
your answer is right, but your units are not The volume is
2500 ft^2 * 10 ft = 25000 ft^3
25000 ft^3 * 1gal/(0.134 ft^3) = 186567 gal
2500 ft^2 * 10 ft = 25000 ft^3
25000 ft^3 * 1gal/(0.134 ft^3) = 186567 gal
Answered by
Ginny
That's right.. sorry 'bout that. Thanks, Mate.
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