Asked by Ty
Two automobiles, each of mass 800kg , are moving at the same speed, 18m/s , when they collide and stick together. At what speed does the wreckage move if one car was driving north and one east.
Answers
Answered by
Damon
initial momentum
North 800 * 18
East 800 * 18
final momentum
North 1600 v sin T
East 1600 v cos T
(I am pretending I do not see that V = 18 sqrt 2 and T = 45 degrees)
800 * 18 = 1600 v sin T
800 * 18 = 1600 v cos T
so sin T = cos T = 1/sqrt 2
That is T = 45 degrees
so
800 * 18 = 1600 v /sqrt2
800 * 18 = 800 v /sqrt 2
v = 18 sqrt 2
v = 18 sqrt 2
North 800 * 18
East 800 * 18
final momentum
North 1600 v sin T
East 1600 v cos T
(I am pretending I do not see that V = 18 sqrt 2 and T = 45 degrees)
800 * 18 = 1600 v sin T
800 * 18 = 1600 v cos T
so sin T = cos T = 1/sqrt 2
That is T = 45 degrees
so
800 * 18 = 1600 v /sqrt2
800 * 18 = 800 v /sqrt 2
v = 18 sqrt 2
v = 18 sqrt 2
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