Asked by Shay
A ball is thrown straight up. Its height, h(in metres), after t seconds is given by h=-5t^2+10t+2. To the nearest tenth of a second, when is the ball 6m above the ground?
Explain why there are two answers.
set h=6
rearrange the quadratic equation to get
5t^2 - 10t + 4=0
Solve using the formula, you should get two positive answers, one will represent the time for its upwards path, and the second the time on its downwards trip.
Explain why there are two answers.
set h=6
rearrange the quadratic equation to get
5t^2 - 10t + 4=0
Solve using the formula, you should get two positive answers, one will represent the time for its upwards path, and the second the time on its downwards trip.
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