During a baseball game, a batter hits a

Question

pop-up to a fielder 78 m away. The acceleration of gravity is 9.8 m/s^2.
If the ball remains in the air for 5.7 s, how high does it rise?
Answer in units of m.

Answer 1

Tf = 5.7/2 = 2.85 s. = Fall time.

h = Yo*t + 0.5g*Tf^2
h = 0 + 4.9*2.85^2 = 39.8 m.