Question

The drawing shows three particles far away from any other objects and located on a straight line. Particle B is located in the middle of particles A and C. The distance between particles A and B is 0.500 m. The distance between particles B and C is 0.250 m. The masses of these particles are mA = 342 kg, mB = 542 kg, and mC = 126 kg. Take the positive direction to be to the right. Find the net gravitational force, including sign, acting on (a) particle A, (b) particle B, and (c) particle C.

Answer 1

draw the diagram. Compute forceAB, and force BC. Trmember force AC.

Force A=AC+AB
Force C= CA+CB
forece on B= AB+BC (watch directions).