A person in a kayak starts paddling, and it accelerates from 0 to 0.59 m/s in a distance of 0.43 m. If the combined mass of the person and the kayak is 72 kg, what is the magnitude of the net force acting on the kayak?

Answer 1

V^2 = Vo^2 + 2a*d
a = (V*2-Vo^2)/2d
a = (0.59^2-0)/0.86 = 0.405 m/s^2.

Fn = m*a = 72 * 0.405 = 29.1 N.