Asked by araf
A girl rows 11 km downstream in 2 h. Her return trip takes 4 h. How fast is the current. in km/h?
Answers
Answered by
Reiny
What is phisecs, some small unit of time?
rowing rate --- x km/h
current rate --- y km/h
A girl rows 11 km downstream in 2 h
---> 2(x+y) = 11
2x + 2y = 11
"Her return trip takes 4 h"
---> 4(x-y) = 11
4x - 4y = 11
first times 2
4x + 4y = 22
add to the 2nd
8x = 33
x = 33/8 km/h
y = (11 - 2(33/8)/2 = 11/8
the current speed is 11/8 km/h
check:
downstream:
2(33/8+11/8) = 2(5.5) = 11
upstream:
4(33/8 - 11/8) = 4(2.75) = 11
My answer is correct!
rowing rate --- x km/h
current rate --- y km/h
A girl rows 11 km downstream in 2 h
---> 2(x+y) = 11
2x + 2y = 11
"Her return trip takes 4 h"
---> 4(x-y) = 11
4x - 4y = 11
first times 2
4x + 4y = 22
add to the 2nd
8x = 33
x = 33/8 km/h
y = (11 - 2(33/8)/2 = 11/8
the current speed is 11/8 km/h
check:
downstream:
2(33/8+11/8) = 2(5.5) = 11
upstream:
4(33/8 - 11/8) = 4(2.75) = 11
My answer is correct!
Answered by
araf
thank you so much !!!
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