Question
If a cylinder’s radius and height are each shrunk down to a third of the original size, what would be the formula to find the modified surface area?
Answers
Steve
a = 2pi r (r+h)
If r and h are shrunk by a factor of 3 each, than we have
2pi (r/3)(r/3 + h/3) = 2/9 pi r (r+h) = 1/9 a
as with all geometric figures, when the linear dimensions are scaled by a factor of f, the area is scaled by f^2 and the volume is scaled by f^3.
If r and h are shrunk by a factor of 3 each, than we have
2pi (r/3)(r/3 + h/3) = 2/9 pi r (r+h) = 1/9 a
as with all geometric figures, when the linear dimensions are scaled by a factor of f, the area is scaled by f^2 and the volume is scaled by f^3.