Asked by queen
A coin is biased such that a head is thrice as likely to occur as a tail. Find the probability distribution of heads and also find the mean and variance of the distribution when it is tossed 4 times.
P(head) + P(tail) = 1
P(head) = 3 P(tail)
Solving gives:
P(head) = 3/4
If we assign 1 to heads and a 0 to tail, then the mean value is 4P(head) = 3, the variance is 4P(head)(1-P(head)) =
3/4
A coin is biased such that a head is thrice as likely to occur as a tail. Find the probability distribution of heads and also find the mean and variance of the distribution when it is tossed 4 times
A coin is biased such that a head is thrice as likely to occur as a tail. Find the probability distribution of heads and also find the mean and variance of the distribution when it is tossed 4 times.
P(head) + P(tail) = 1
P(head) = 3 P(tail)
Solving gives:
P(head) = 3/4
If we assign 1 to heads and a 0 to tail, then the mean value is 4P(head) = 3, the variance is 4P(head)(1-P(head)) =
3/4
A coin is biased such that a head is thrice as likely to occur as a tail. Find the probability distribution of heads and also find the mean and variance of the distribution when it is tossed 4 times
A coin is biased such that a head is thrice as likely to occur as a tail. Find the probability distribution of heads and also find the mean and variance of the distribution when it is tossed 4 times.
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Anonymous
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