I am sorry. I need a picture.
in general each leg must take weight/6
if 37 is from vertical then Tension* cos 37 = weight/6
Some insects can walk below a thin rod (such as a twig) by hanging from it. Suppose that such an insect has mass m and hangs from a horizontal rod as shown in the figure, with angle θ = 37°. Its six legs are all under the same tension, and the leg sections nearest the body are horizontal. What is the ratio of the tension in each tibia (forepart of a leg) to the insect's weight?
2 answers
with this problem, we don have the weight but we do no that the tibia of the insect is in the y-axis in relations to theta so:
a)6Tsin40=mg
T=mg/6sin40 --> expressing this as the bugs weight, gives us T/mg = 0.3
b) note that the insect legs have been slightly bent so as the legs opens, theta is going to increase making T to decrease.
a)6Tsin40=mg
T=mg/6sin40 --> expressing this as the bugs weight, gives us T/mg = 0.3
b) note that the insect legs have been slightly bent so as the legs opens, theta is going to increase making T to decrease.
1 answer