A 55 kg box is pulled with constant speed across the floor with a rope that is at an angle of 40 degrees above the horizontal. If the tension in the rope is 125n what is the coefficient of friction between the box and the floor?

Answer 1

pull force = 125 cos 40

lift force = 125 sin 40

Fdown on floor= 55*9.81 - 125 sin 40

friction force back = Fdown*mu

F = m a = 0
so
125 cos 40 = Fdown * mu

Answer 2

95.75 N correct??