What is the integral of [(2x-y)^3]dx?
3 answers
Sorry I mean [(2x-y)^2]dx
since x is the variable of integration, y acts just like any other constant, so it's just
(1/8)(2x-y)^4 + C
(1/8)(2x-y)^4 + C
sorry - I mean
(1/6)(2x-y)^3 + C
(1/6)(2x-y)^3 + C
1 answer