Asked by Miley
                Why is ln(e^-2) = -2.
Why doesn't it = e^-2??
            
        Why doesn't it = e^-2??
Answers
                    Answered by
            Damon
            
    ln (e^x) =  x ln e = x * 1 = x
    
                    Answered by
            Miley
            
    so what if it was ln5(e^-2). would the answer be -10?? thanks for your help:)
    
                    Answered by
            Damon
            
    No, it is only because ln is base e that ln(e^x) = x
in general
loga (a^x) = x loga(a) = x*1 = x
log 5 of 5 is 1, but log5 (e) is not one
    
in general
loga (a^x) = x loga(a) = x*1 = x
log 5 of 5 is 1, but log5 (e) is not one
                    Answered by
            Miley
            
    okay thanks
    
                    Answered by
            Damon
            
    it is all because
b^logb (x) = x
so
5^log5 (5) = 5
so log5 (5) has to be 1
    
b^logb (x) = x
so
5^log5 (5) = 5
so log5 (5) has to be 1
                    Answered by
            Miley
            
    thanks damon!!!!!!
    
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