Asked by Gerald

The area of a rectangle is 44yds squared, and the length of the rectangle is 3yds less than twice the width. what is the length and width
Answered by Reiny
width ---- x
length --- 2x - 3

x(2x-3) = 44
2x^2 - 3x - 44 = 0
(x + 4)(2x - 11) = 0
x = -4, which would make no sense
or
x = 11/2 or 5.5 yds

the width is 5.5 yrds and the length is 8 yards

check:
8(5.5) = 44

Answered by mohammed
a=l*w 44=3-2x , 2x=44-3, 2x=39
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