Asked by Gabriella
                A 1277 mL sample of nitrogen (N2) was collected by displacement of water at 24 degrees C under a total barometric pressure of 966 torr. What mass of dry nitrogen was collected? The vapor pressure of water at 24 degrees C is 22 torr.
Answer in units of g
            
        Answer in units of g
Answers
                    Answered by
            DrBob222
            
    Use PV = nRT and calculate n.
P in torr wet H2 = 966 torr
P H2O torr = 22 torr
PH2 dry = 966-22 = ?
PH2 in atm = ?/760
V = 1.277 L
n = unknown--Solve for this.
R = 0.08206 L*atm/mol*K
T = 297K
Find n, then n = grams/molar mass. You know n and molar mass, solve for grams.
    
P in torr wet H2 = 966 torr
P H2O torr = 22 torr
PH2 dry = 966-22 = ?
PH2 in atm = ?/760
V = 1.277 L
n = unknown--Solve for this.
R = 0.08206 L*atm/mol*K
T = 297K
Find n, then n = grams/molar mass. You know n and molar mass, solve for grams.
                    Answered by
            Maria
            
    1.59g
    
                    Answered by
            George
            
    I don't know how to do this at all, but I wanted to offer you my sincerest thanks for answering this question. So often I come to this website expecting help with my chemistry work from like-minded peers but so often my dreams are dashed. And so I just wanted to thank you for helping me become the man I am today. 
    
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