Asked by Anonymous
Can some please help me work out each of these systems?
1. 4y=13+2x
6x+4y=9
2. Y=6-2x
5x=14-3y
3. 4x-6y=15
6x=10+4y
1. 4y=13+2x
6x+4y=9
2. Y=6-2x
5x=14-3y
3. 4x-6y=15
6x=10+4y
Answers
Answered by
Steve
since I just showed you how to do three others just like these, do you have any ideas on these?
elimination or substitution will work fine.
elimination or substitution will work fine.
Answered by
Anonymous
Please help me I don't get how to move the equation around. At least just set up the equation for me.
Answered by
Steve
for elimination, you want all the equations to look the same, so it's easy to add/subtract. The usual way is to give them the form
ax+by = c
So, for #1, we have
4y=13+2x
6x+4y=9
On the first one, subtract 2x from each side and you have
-2x+4y = 13
the 2nd is ok, so you now have
-2x+4y = 13
6x+4y = 9
If you subtract, the y's go away and you have
-8x = 4
x = -1/2
Now you can plug that into either equation to find y.
For substitution, isolate one variable and substitute into the other equation. For #2, we have
y=6-2x
5x=14-3y
The first equation already shows us what y must be, so put it into the second equation to get
5x = 14-3(6-2x)
5x = 14-18+6x
-x = -4
x = 4
now use that to get y.
Go ahead and try either method on the 3rd problem and if you get stuck, come on back for further pointers.
ax+by = c
So, for #1, we have
4y=13+2x
6x+4y=9
On the first one, subtract 2x from each side and you have
-2x+4y = 13
the 2nd is ok, so you now have
-2x+4y = 13
6x+4y = 9
If you subtract, the y's go away and you have
-8x = 4
x = -1/2
Now you can plug that into either equation to find y.
For substitution, isolate one variable and substitute into the other equation. For #2, we have
y=6-2x
5x=14-3y
The first equation already shows us what y must be, so put it into the second equation to get
5x = 14-3(6-2x)
5x = 14-18+6x
-x = -4
x = 4
now use that to get y.
Go ahead and try either method on the 3rd problem and if you get stuck, come on back for further pointers.
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