Asked by Anonymous

Teri, nick, and Alex had $865 altogether. Teri spent 2/5 of her money. Nick spent $40, and Alex spent twice as much as Alex. If the three friends had the same amount of money left, how much money did Alex have in the beginning?
Answered by Reiny
Looking at all the "Related Questions" below, you must have a typo.
Most say "Alex spent twice as much as Terry"

let Terry's amount be x
let Nick's amount be y
let Alex' amount be 865-x-y

after the spending:
Terry has (3/5)x = 3x/5
Nick has y-40

Terry spend 2x/5
so Alex spent 4x/5
and Alex has left 865-x-y - 4x/5
= (4325-5x-5y - 4x)/5
= (4325 - 9x - 5y)/5

all have the same amount left over ...
3x/5 = y-40
3x= 5y - 200
3x - 5y = -200 , #1

(4325 - 9x - 5y)/5 = y-40
4325 - 9x - 5y = 5y - 200
9x + 10y = 4525 , #2

#1 times 2
6x - 10y = -400
9x - 10y = 4525
add them ...
15x = 4125
x = 275
then in #1:
3(275) - 5y = -200
y = 205

Terry had 275
Nick had 205
Alex had 865-275-200 = 385

check:
Terry has (3/5)275 or 165 left
Nick has 205-40 or 165 left
Terry spent (2/5)(275) or 110, so
Alex spent 220
leaving him with 385-220 = 165
ALL LOOKS GOOD
Answered by Darkunicornz
itz 2/5 for Teri so you didyour math wrong
Answered by Darkunicornz
Nevermind you're fine
There are no AI answers yet. The ability to request AI answers is coming soon!