Asked by Anonymous
A high school senior vacationing in Jamaica for her senior class trip jumped off a 20 foot cliff into a pool of water. The height of the senior above the water is modeled by the function
h(t)=-t^2+t/4+5/4
where h(t) is the height of the senior above the water in feet t seconds after jumping off the cliff. How many seconds will it take for the senior to reach the water?
h(t)=-t^2+t/4+5/4
where h(t) is the height of the senior above the water in feet t seconds after jumping off the cliff. How many seconds will it take for the senior to reach the water?
Answers
Answered by
Damon
Where did you find this problem?
at t = 0, the senior has to be at 20 feet I think.
however your function shows her at 1.25 feet at t = 0
That is not right.
Moreover in real life h = Hi + Vi t -(1/2) g t^2
in the feet/seconds system
-(1/2) g t^2 is about -16 t^2
NOT -t^2
at t = 0, the senior has to be at 20 feet I think.
however your function shows her at 1.25 feet at t = 0
That is not right.
Moreover in real life h = Hi + Vi t -(1/2) g t^2
in the feet/seconds system
-(1/2) g t^2 is about -16 t^2
NOT -t^2
Answered by
Anonymous
found it in my math homework... I thought it was a weird one too. Thank you
Answered by
Damon
As it is stated it is impossible to solve because you can not start at both 20 and at 1.25 feet :)
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