Asked by Meli
A mathematical model for concentration of administered cortisone in humans over a 24-hour period uses the function
C= [(D x a) / V(a-b)] (e^(-bt)-e^(-at)
where C is the concentration, D is the dose given at time t=0, V is the volume of distribution (volume divided by bioavailability), a is the absorption rate, b is the elimination rate, and t is the time in hours.
a.)What is the value of C at t=0? Explain why this makes sense.
b.)What happens to the concentration as a large amount of time passes? Explain why this makes sense.
c.)The researchers used the values D=500 micrograms, a=8.5, b=0.09, and V=3,700 liters. Use these values and a graphing calculator to estimate when the concentration is greatest.
C= [(D x a) / V(a-b)] (e^(-bt)-e^(-at)
where C is the concentration, D is the dose given at time t=0, V is the volume of distribution (volume divided by bioavailability), a is the absorption rate, b is the elimination rate, and t is the time in hours.
a.)What is the value of C at t=0? Explain why this makes sense.
b.)What happens to the concentration as a large amount of time passes? Explain why this makes sense.
c.)The researchers used the values D=500 micrograms, a=8.5, b=0.09, and V=3,700 liters. Use these values and a graphing calculator to estimate when the concentration is greatest.
Answers
Answered by
Steve
C(0) = 0
Naturally, at t=0, there has been no drug added
As t->∞, e^-bt and e^-at ->0, so we again have
C(∞) = 0
All the drug has been absorbed or eliminated.
If
C(t) = (500)(8.5)/(3700)(8.5-0.09) (e^-0.09t - e^-8.5t)
then max C is at t=0.54
Naturally, at t=0, there has been no drug added
As t->∞, e^-bt and e^-at ->0, so we again have
C(∞) = 0
All the drug has been absorbed or eliminated.
If
C(t) = (500)(8.5)/(3700)(8.5-0.09) (e^-0.09t - e^-8.5t)
then max C is at t=0.54
Answered by
Damon
I assume D x a means D a
I know nothing about medicine but
a) at t = 0, e^0 = 1
so
C(0) = something(1-1) = 0
It has not had time to be absorbed
after a long time, both e^-bt and e^-at approach zero so the concentration approaches zero. At first assuming a is much bigger than b the absorption will dominate, but after a long time the elimination rate balances the absorption.
go ahead, do C
I know nothing about medicine but
a) at t = 0, e^0 = 1
so
C(0) = something(1-1) = 0
It has not had time to be absorbed
after a long time, both e^-bt and e^-at approach zero so the concentration approaches zero. At first assuming a is much bigger than b the absorption will dominate, but after a long time the elimination rate balances the absorption.
go ahead, do C
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.