The position of a function of a moving particle is s(t)=5+4t-t^2 for 0<t<10 where s is in meters and t is measured in seconds. What is the maximum speed in m/sec of the particle on the interval [0,10]?

Answer 1

v(t) = 4-2t
dv/dt = -2
There is no local min/max, and v is constantly decreasing, so max v in the interval is at t=0, or v=4