Question

For chem we did a kinetics lab based on the rate of reaction of peroxydisulfate ion with iodide ion.

I'm supposed to find the amount of S2O3 ^2- consumed for every trial (in moles)

If someone could just explain how to do that with the information I currently have, that would be perfect!

The time taken for the consumption of N2S2O3 at 1.0ml is 2:46 (min:sec). The concentration of Na2S2O3 is 0.20M. There is 0.0002 moles of Na2S2O3 present in a 1.0ml aliquot of Na2s2O3 solution.

I may be overthinking this. Sorry.

Answer 1

mols = M x L

Answer 2

So it would be (0.20M)(1.0ml/1000L)=0.0002moles of S2O3 consumed ?

Answer 3

For each mL you used it is that, yes. I don't know the details of the experiment but if all of the 1 mL was consumed then the amount consumed is M x L = ?, yes.