What's your problem with these problems?
a. (9/5)*21]+32 = ?F
b. (F-32)*5/9 = ?C
c. There are 1E9 nm in a m and 1000 m in a km.
a. convert 21 C Celsius to degrees Fahrenheit.
b. convert 101 F Fahrenheit to degrees Celsius.
c. convert 15 nm into km.
a. (9/5)*21]+32 = ?F
b. (F-32)*5/9 = ?C
c. There are 1E9 nm in a m and 1000 m in a km.
°F = (°C × 9/5) + 32
Now, let's plug in the given value of 21°C into the formula:
°F = (21 × 9/5) + 32
°F = (189/5) + 32
°F = 37.8 + 32
°F ≈ 69.8
Therefore, 21°C is approximately equal to 69.8°F.
b. To convert Fahrenheit to Celsius, you can use the formula:
°C = (°F - 32) × 5/9
Now, let's plug in the given value of 101°F into the formula:
°C = (101 - 32) × 5/9
°C = 69 × 5/9
°C = 345/9
°C ≈ 38.3
Therefore, 101°F is approximately equal to 38.3°C.
c. To convert nanometers (nm) to kilometers (km), you need to divide the value of nanometers by 1 billion (since there are 1 billion nanometers in a kilometer).
Let's work through the conversion using the given value of 15nm:
km = 15nm / 1,000,000,000
km = 0.000000015km
Therefore, 15nm is equal to 0.000000015km.