(S2) = 11.0mols/5.20L = approx 2 but you need to be more accurate.
.........S2 + C ==> CS2
I mols...2..xs...0
C.......-x..xs...x
E......2-x..xs...x
Kc = (CS2)/(S2) note:C doesn't appear in the Kc exprssion because it is a solid.
Substitute the E line into Kc expression and solve for x = (CS2) = M in mols/L.
total mols = M x L = ?
grams = mols x molar mass = ?
S2 + C ----> CS2
How many grams of CS2 can be prepared by heating 11.0 moles of S2 with excess carbon in 5.20 L reaction vessel held at 900 kelvin until equilibrium is attained?
Kc= 9.40
1 answer