Asked by katie
A scuba tank is filled to 2500 psi(170 atm) in a dive shop at room temp/(25 degrees C) then stored in the trunk of a car on a hot day. What will be the new pressure in the tank if the temp. in the trunk reaches 60 degrees C? Express that pressure in atmospheres, not psi.
Answers
Answered by
DrBob222
(P1V1)/T1 = (P2V2)/T2
Use 170 atm for P1 and the answer will be in atm. Don't forget to use Kelvin for T1 and T2.
Use 170 atm for P1 and the answer will be in atm. Don't forget to use Kelvin for T1 and T2.
Answered by
katie
i don't understand this at alll
Answered by
DrBob222
You plug in 170 atm for P1, there is no V1 or V2 in the problem, and T1 = 25 degrees C which si 273 + 25 = ??Kelvin. Continuing, P2 is what you want to know, V2 is not in the problem, and T2 is 60 degrees which must be convert to Kelvin. Then solve for P2.
Answered by
katie
okay so does it kinda look like this
(170)/298/333...i kinda understand not really
(170)/298/333...i kinda understand not really
Answered by
DrBob222
We have P1/T1 = P2/V2
You have P1 in the right place with the right number. Yuo have 298 ok. I don't see an equal sign. I don't see P2 (which you're solving for) and the 333 (the right number Kelvin) is not in the right place. Follow the guideline above. The equation is
P1/T1 = P2/T2.
Solve for P2 but substitute the numbers first and solve it step by step.
You have P1 in the right place with the right number. Yuo have 298 ok. I don't see an equal sign. I don't see P2 (which you're solving for) and the 333 (the right number Kelvin) is not in the right place. Follow the guideline above. The equation is
P1/T1 = P2/T2.
Solve for P2 but substitute the numbers first and solve it step by step.
Answered by
katie
ok so 170/298=P2/333
which is .570...how do i find P2
which is .570...how do i find P2
Answered by
katie
ok so 170/298=P2/333
which is .570...how do i find P2
which is .570...how do i find P2
Answered by
DrBob222
<b>
170/298 = P2/333
0.570 = P2/333
P2 = 0.570 x 333 = ?? atm.</b>
170/298 = P2/333
0.570 = P2/333
P2 = 0.570 x 333 = ?? atm.</b>
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