A student begins with 9.7 mL of a 0.26 M Cu(NO3)2 solution and performs copper cycle lab. She recovers 0.075 grams of copper metal.

Question

A) What is the Theoretical Yield
B) What is the Actual Yield
C) What is the Percent Yield

Answer 1

I don't know what a copper cycle lab is.
a. mols Cu(NO3)2 = M x L = ?
1 mol Cu in 1 mol Cu(NO3)2
g Cu = mols x atomic mass = theoretical yield

b. 0.075 from the problem.
c. (actual/theoretical)*100 = %yield

Answer 2

Thank you! I was just missing the step of multiplying by atomic mass! :)