Asked by jay

An object with an initial velocity of 12 m/s west experiences a constant acceleration of 4 m/s^2 west for 3 seconds. During this time the object travels a distance of:
Answered by Henry
V = Vo + a*t = 12 + 4*3 = 24 m/s = Final
velocity.

d=(V^2-Vo^2)/2a = (24^2-12^2)/8 = 54 m.
Answered by مجمد
54
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