Asked by Temmick

This equation decribes oxidation of acidified solution of sodium oxalate(Na2C2O4) by potassium permanganate(KMnO4):
5 C2O4^2- + 2Mn04^- + 16H2SO4 to produce 10Co2 + 2Mn^2- + 16HSO4^- + 8H2O.
what volume of 0.127M sodium oxalate in sulphuric acid will react with 3.57g of potassium permanganate?

I got 177ml as my answer. Not sure if it is right. Pls help A.S.A.P .
Thanks

11 years ago

Answered by DrBob222

I didn't get 177 mL.
mols KMnO4 = grams/molar mass
mols Na2C2O4 = mols KMnO4 x (5 mols ox/2 mol MnO4) = ?
Them M Na2C2O4 = mols/L
Solve for L and convert to mL.

11 years ago

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