Question
If you can throw a stone straight up to a height of 18m, how far could you throw it horizontally over level ground? Assume the same throwing speed and optimum launch angle.
Answers
fall from 18 m, what is speed
(1/2) m v^2 = m g h
vlaunch = sqrt(2 gh)
that is your launch speed for second part
optimum launch angle is 45 degrees. so do horizontal and vertical problems
u = horizontal velocity = vlaunch/sqrt 2
Vi = initial speed up = vlaunch/sqrt2
distance = u * t
find t from vertical problem, up and down
(1/2) m v^2 = m g h
vlaunch = sqrt(2 gh)
that is your launch speed for second part
optimum launch angle is 45 degrees. so do horizontal and vertical problems
u = horizontal velocity = vlaunch/sqrt 2
Vi = initial speed up = vlaunch/sqrt2
distance = u * t
find t from vertical problem, up and down