Asked by John

If you can throw a stone straight up to a height of 18m, how far could you throw it horizontally over level ground? Assume the same throwing speed and optimum launch angle.

Answers

Answered by Damon
fall from 18 m, what is speed
(1/2) m v^2 = m g h
vlaunch = sqrt(2 gh)
that is your launch speed for second part


optimum launch angle is 45 degrees. so do horizontal and vertical problems
u = horizontal velocity = vlaunch/sqrt 2
Vi = initial speed up = vlaunch/sqrt2
distance = u * t
find t from vertical problem, up and down
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