Asked by Ann
Seventeen people has been exposed to a particular disease. Each one independently has a 40% chance of contracting the disease. A hospital has the capacity to handle 10 cases of the disease. What is the probability that the hospital's capacity will be exceeded?
a- .011
b- .736
c- .965
d- .989
e- .035
a- .011
b- .736
c- .965
d- .989
e- .035
Answers
Answered by
MathGuru
Use the binomial probability function:
P(x) = (nCx)(p^x)[q^(n-x)]
n = 17
x = 11 through 17
p = 0.4
q = 1 - p = 0.6
Find P(11) through P(17). Add together for your probability.
Note:
You can also use a binomial probability function table with the values listed to find the probability as well. It is an easier way of doing this problem.
Hint:
Answer should be .035 (rounded)
I hope this will help get you started.
P(x) = (nCx)(p^x)[q^(n-x)]
n = 17
x = 11 through 17
p = 0.4
q = 1 - p = 0.6
Find P(11) through P(17). Add together for your probability.
Note:
You can also use a binomial probability function table with the values listed to find the probability as well. It is an easier way of doing this problem.
Hint:
Answer should be .035 (rounded)
I hope this will help get you started.
Answered by
Anonymous
.035
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