Question
A car travels 3.0km due west and then 2.0km to the north. Find the magnitude and
direction of the car’s resultant displacement?
direction of the car’s resultant displacement?
Answers
Henry
X = -3.0km
Y = 2km
Tan Ar = Y/X = 2/-3 = -0.66667
Ar = -33.69o = Reference angle.
A = -33.69 + 180 = 146.3o, CCW.
D=X/cos A = -3/cos146.3=3.61km[146.3o]
Y = 2km
Tan Ar = Y/X = 2/-3 = -0.66667
Ar = -33.69o = Reference angle.
A = -33.69 + 180 = 146.3o, CCW.
D=X/cos A = -3/cos146.3=3.61km[146.3o]