Asked by Andy
A car travels 3.0km due west and then 2.0km to the north. Find the magnitude and
direction of the car’s resultant displacement?
direction of the car’s resultant displacement?
Answers
Answered by
Henry
X = -3.0km
Y = 2km
Tan Ar = Y/X = 2/-3 = -0.66667
Ar = -33.69o = Reference angle.
A = -33.69 + 180 = 146.3o, CCW.
D=X/cos A = -3/cos146.3=3.61km[146.3o]
Y = 2km
Tan Ar = Y/X = 2/-3 = -0.66667
Ar = -33.69o = Reference angle.
A = -33.69 + 180 = 146.3o, CCW.
D=X/cos A = -3/cos146.3=3.61km[146.3o]
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