Question

If a 65 kilogram load was raised 6 meters in 60 seconds determine the minimum rated wattage of the motor needed to accomplish this assuming the motor is 75% efficient. give your answer in W.

Answer 1

F = 65 * 9.81 Newtons
energy = F*d = 65*9.81*6 Joules
energy/unit time = power = 65*9.81*6/60 watts
divide by .75
65*9.81*6/(60*.75)

Answer 2

thanks so much!!!

Answer 3

You are welcome !