Asked by CMC
A man steps off a 100 m diving platform. How long will it take him to
drop the …first 50 m? How long will it take him to drop the second 50 m?
drop the …first 50 m? How long will it take him to drop the second 50 m?
Answers
Answered by
Henry
Vo*t + 0.5g*t^2 = 100-50 = 50
0 + 4.9t^2 = 50
t^2 = 10.20
t = 3.19 s.
V = Vo + g*t = 0 + 9.8*3.19 = 31.3 m/s =
The velocity after the 1st 50 m drop =
The initial velocity (Vo) for the 2nd 50 m drop.
31.3*t + 4.9t^2 = 50
4.9t^2 + 31.3t - 50 = 0
t = 1.32 s.(Use Quad. Formula).
0 + 4.9t^2 = 50
t^2 = 10.20
t = 3.19 s.
V = Vo + g*t = 0 + 9.8*3.19 = 31.3 m/s =
The velocity after the 1st 50 m drop =
The initial velocity (Vo) for the 2nd 50 m drop.
31.3*t + 4.9t^2 = 50
4.9t^2 + 31.3t - 50 = 0
t = 1.32 s.(Use Quad. Formula).
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