To solve the system of equations given by
- \( 100y + 50x = 100 \)
- \( -25x + 50y = 50 \)
we can rewrite these equations in a more manageable form and check the provided answer choices.
First, let's simplify both equations.
-
Divide the first equation by 50:
\[ 2y + x = 2 \quad \text{(Equation 1)} \]
-
Divide the second equation by 25:
\[ -x + 2y = 2 \quad \text{(Equation 2)} \]
Now we can rearrange Equation 1 to express \(x\) in terms of \(y\):
\[ x = 2 - 2y \]
Next, substitute \(x\) into Equation 2:
\[ -(2 - 2y) + 2y = 2 \]
Distributing the negative:
\[ -2 + 2y + 2y = 2 \] \[ 4y - 2 = 2 \] \[ 4y = 4 \] \[ y = 1 \]
Now substitute \(y = 1\) back into the equation for \(x\):
\[ x = 2 - 2(1) = 0 \]
So we have the solution:
\[ (x, y) = (0, 1) \]
None of the other answer choices (-100, 100), (1, 100), (100, 1) are valid solutions.
Thus, the correct answer is:
\((0, 1)\)