5H2C2O4 + 2KMnO4 + 3H2SO4 ==> 10CO2 + 8H2O + 2MnSO4 + K2SO4
millimoles KMnO4 = mL x M = 35 mL x 0.04 M = 1.4
millimoles H2C2O4 = 1.4 mmols KMnO4 x (5 mols H2C2O4/2 mols KMnO4) = 1.4 x 5/2 = 3.5
Then M H2C2O4 = millimoles/mL = 3.5/100 = ? M
100mL of oxalic acid (H2C2O4) requires 35mL of 0.04 M KMnO4 to titrate it to the endpoint. calculate the molarity of the oxalic acid
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