Asked by Rachell
On an unknown planet, a pendulum of length 1.5 m swings with a period of 3.3 s. What is the acceleration of gravity on this planet?
Answers
Answered by
Damon
T = 2 pi sqrt (L/g)
3.3 = 2 pi sqrt (1.5/g)
sqrt(1.5/g)= .5252
1.5/g = .276
g = 5.44 m/s^2 around half earth g
3.3 = 2 pi sqrt (1.5/g)
sqrt(1.5/g)= .5252
1.5/g = .276
g = 5.44 m/s^2 around half earth g