Asked by Julie
Ammonium chloride and sodium nitrite react to form sodium chloride, water and nitrogen gas. If 6.33 moles of ammonium chloride react with sodium nitrite, how many grams of sodium chloride will be produced?
Answers
Answered by
DrBob222
NH4Cl + NaNO2 ==> NaCl + N2 + 2H2O
6.33 mols NH4Cl x (1 mol NaCl/1 mol NH4Cl) = 6.33 mols NaCl formed.
Then g = mols x molar mass.
6.33 mols NH4Cl x (1 mol NaCl/1 mol NH4Cl) = 6.33 mols NaCl formed.
Then g = mols x molar mass.