Asked by Anna
Find two numbers whose difference is 132 and whose product is a minimum.
Answers
Answered by
Reiny
smaller number --- x
larger number ----- x + 132
product=P=x(x+132)
= x^2 + 132x
dP/dx = 2x + 132
=0 for a min of P
2x = -132
x = -66
the smaller is -66
the larger -66+132 or +66
the two numbers are -66 and +66
larger number ----- x + 132
product=P=x(x+132)
= x^2 + 132x
dP/dx = 2x + 132
=0 for a min of P
2x = -132
x = -66
the smaller is -66
the larger -66+132 or +66
the two numbers are -66 and +66
Answered by
gabriel
didn't understand that method
Answered by
zeborah
its very smart way for a explanation but doesn't really make sense
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