Asked by Anonymous
In Cambridge, England, a seconds pendulum is 0.9942 m long. What is the free-fall acceleration in Cambridge? (Use 4 significant figures in your answer.)
Answers
Answered by
bobpursley
T=2PIsqrt(l/g)
l/g= T^2/2PI
g= l*2PI/l use 3.14159 for pi or better.
l/g= T^2/2PI
g= l*2PI/l use 3.14159 for pi or better.
Answered by
m
0.1007
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