Asked by JM
One angle of a triangle measures 100. the other two angles are in a ratio of 3:5. What are the measures of those two angles?
Answers
Answered by
Reiny
let the two unknown angles be 3x and 5x
3x + 5x + 100 = 180
......
take over
3x + 5x + 100 = 180
......
take over
Answered by
dhruv
i do not know the answer, i need help please
Answered by
Anonymous
3x+5x+100=180
-100 -100
3x+5x=80
8x=80
x=10
3(10)=30
5(10)=50
-100 -100
3x+5x=80
8x=80
x=10
3(10)=30
5(10)=50
Answered by
maxycleferner
thank you for your generous donation
Answered by
gaura thakur
let the ratio be 3x ,5x
the sum of all angles of triangle = 180
3x + 5x + 100 = 180
8x = 180 -100
x = 80/8
x = 10
now,
3x = 3 x 10
= 30
5x = 5 x 10
= 50
the sum of all angles of triangle = 180
3x + 5x + 100 = 180
8x = 180 -100
x = 80/8
x = 10
now,
3x = 3 x 10
= 30
5x = 5 x 10
= 50
Answered by
Lia
One angle of a triangle measures 100. the other two angles are in a ratio of 3:5. What are the measures of those two angles?
So 100 + 3x + 5x = 180
100 + 8x = 180
8x = 80
x = 10
Now plug it in to your ratio, which is 3:5 so 30 and 50,
30 + 50 + 100 = 180
So 100 + 3x + 5x = 180
100 + 8x = 180
8x = 80
x = 10
Now plug it in to your ratio, which is 3:5 so 30 and 50,
30 + 50 + 100 = 180
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