Asked by McKenna Louise
1. ABC Feeds has two different types of cattle feed containing crude protein in the amount of 45% and 20% respectively. How many of each type must a feed lot manager mix together to obtain 10 000lbs of a mixture that is 25% protein?
2. Meg has a solution that is 40% alcohol and another solution that is 60% alcohol. If Meg wants 12gal of a solution that is 45% alcohol, how much of the two solutions must he mixed?
2. Meg has a solution that is 40% alcohol and another solution that is 60% alcohol. If Meg wants 12gal of a solution that is 45% alcohol, how much of the two solutions must he mixed?
Answers
Answered by
bobpursley
10,000*.25=(10,000-x).45 + x*.20
where x is the amount of twenty percent.
2.
12*.45=x*.40+(12-x).60
x is the amount of forty percent
where x is the amount of twenty percent.
2.
12*.45=x*.40+(12-x).60
x is the amount of forty percent
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