Asked by Astro
using a powerful air gun, a steel ball is shot vertically upward with a velocity of 80 m/s, followed by another shot after 5 seconds. find the initial velocity of the second ball to meet the first ball 150 m from the ground.
Answers
Answered by
bobpursley
first ball:
hf=vi1t-4.9t^2
second ball
hf=vi2(t-5)-4.9 (t-5)^2
you know vi1, hf. You do not know t, vi2.
in the first equation, solve for t.
then, in the second equation, solve for vi2
hf=vi1t-4.9t^2
second ball
hf=vi2(t-5)-4.9 (t-5)^2
you know vi1, hf. You do not know t, vi2.
in the first equation, solve for t.
then, in the second equation, solve for vi2
Answered by
WEW
THE ANSWER IS NEGATIVE VELOCITY WHAT THE PAK
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